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(I) Super Invar'", an alloy of iron and nickel, is a strong material with a very low coefficient of thermal expansion $\left(0.20 \times 10^{-6} / \mathbf{C}^{\circ}\right) .$ A 1.6 $\mathrm{-m}$ -long tabletop made of this alloy is used for sensitive laser measurements where extremely high

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$9.6 \times 10^{-5} \mathrm{m}$

Physics 101 Mechanics

Chapter 17

Temperature, Thermal Expansion, and the Ideal Gas Law

Temperature and Heat

University of Michigan - Ann Arbor

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University of Sheffield

Lectures

01:59

(I) Super Invar $^{\mathrm…

05:56

(I) Super Invar$^\mathrm{T…

02:42

(I) Super Invar'M, an…

03:17

03:24

Super Invar, an alloy of i…

01:27

A hypothetical metal alloy…

01:08

02:19

It is desirable to produce…

01:43

A 0.4-m (15.7-in.) rod of …

01:03

A $0.4 \mathrm{m}(15.7 \te…

01:42

Thermal expansion seems li…

02:03

01:00

A wire of Nichrome (a nick…

So, um, Ali off in a Necco. Strong material. Very low coefficient of thermal expansion, which is no 0.2 times 10 to the minus six. Divided by degrees Celsius. Um, per degree sells is a 1.6 meter long table top is made of This outlying is used for sensitive laser measurements were extremely high. Tolerance is required. How much will this alloy table expand upon its length if the temperature is increased? Thio five hazing creased by five degrees Celsius on compared this toe, how much still on would increase. So, um, we give analogue for valley to denote the coefficient of thermal expansion. So, in this case, Alf, um, a for alloy is equal Thio no point to turnings 10 to the minus six, um, on the unit iss degrees. So c'est to the minus one. Um, we give our coefficient, um, off. Uh, still, as the Alfa s now online values s. So if you look up reference, that is the very first still, um, the most. Come on that that I seem to be familiar with his 13 times 10 to the minus six. However, the solutions to this question require you to use the value off 12 times 10 to the minus six, uh, degree Celsius. So the minus one eso In order to find the change of length eso delta l is equal to, uh, Alfa, uh, times by change of temperature. Um, on times by a length. Um, So, uh, in the first instance with the super strong ally, we said s o in part one, Alfa is the value of Alfa A Has given Delta T for both parts of the question. So it's actually weaken. Say the delta T hair is ah equal to five on dhe. Our is equal to 1.6. So substituting the, uh, first out for a into there, we have a delta l a is equal Thio Uh, no, Huh is equal. Thio ah is equal to 1.6 times 10 to the minus six. So so shooting in perfecting that in tow. Online calculator. So 1.6 times 10 to the minus six Um ah nde her delta How ah s for still some shooting the three values into an online calculator? Um, we get that. The change in length of still is 9.6 times 10 to the minus five equals mine. 50.6 times 10 to the minus five. Announcer compared them. Um, way will. D'oh Delta. I'll ask over Delta. Uh, how a on that is equal to 60. So the ratio, it's 60 times. I hope that makes sense.

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