00:01
All right, so problem number 36 wants us to figure out if you're given the b -mazon, a cork combination as b -minus is equal to be a bottom cork and an anti -up cork.
00:23
So we need to verify that this is actually a physical combination.
00:29
So to do that, we need to verify all the conservation.
00:31
Rules.
00:32
So first let's look at charge.
00:37
So for charge, we have a minus one for the b -mazon is equal to.
00:43
Now, corks are kind of weird.
00:45
They carry one -third charge or one -third or two -third charges instead of one -half and one charges, basically, or instead of integer charges.
00:56
So they carry a third -third or so for a bottom quark, it's a minus one -third plus an upcork, an anti -upcourt.
01:08
One, upcork carries a plus two -thirds charge.
01:11
So an anti -upcork carries a minus two -thirds charge.
01:15
So this is concerned.
01:20
Okay, so now we've got the baryon number.
01:27
So for the beryon number, we've got zero for the b -mazon is equal to.
01:34
Now the barion numbers for quarks are, again, and they're weird.
01:39
They're a third.
01:40
So one -third for the bottom cork plus the upcork would be one -third, and the anti -up quark is minus one -third.
01:50
So minus one -third, one -third plus one -third is equal to zero, so that's conserved.
01:57
Now let's look at strangeness.
02:05
Strangeness, so the strangeness of a b -mazon is zero, and the strangeness of the bottom and upcorks are both zero.
02:19
So now let's look at the three characteristic of corks, the charm, the topness, and the bottomness.
02:27
So let's start with charm.
02:32
The b.
02:33
Mazon is zero.
02:35
And the bottom and the upcork are both have zero charm.
02:39
So that's conserved.
02:42
Now let's look at top.
02:49
The topness of the b.
02:50
Maison is zero.
02:51
And the bottom and up quarks both have zero topness as well.
02:57
So that's conserved.
02:59
Now, finally, that brings us to bottomness...