Question

(I) The electric field between two parallel plates connected to a 45-V battery is $1300 \mathrm{~V} / \mathrm{m}$. How far apart are the plates?

   (I) The electric field between two parallel plates connected to a 45-V battery is $1300 \mathrm{~V} / \mathrm{m}$. How far apart are the plates?

Physics for Scientists and Engineers with Modern Physics

Physics for Scientists and Engineers with Modern Physics

Douglas C. Giancoli 4th Edition

Chapter 23, Problem 6

Instant Answer

Solved by Expert Prashant Bana

03/12/2021

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Step 1: We are given the potential difference ($\Delta V$) between the plates as 45 V and the electric field ($E$) between the plates as 1300 V/m. Show more…

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(I) The electric field between two parallel plates connected to a 45-V battery is $1300 \mathrm{~V} / \mathrm{m}$. How far apart are the plates?

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Key Concepts

Potential Difference

Potential difference, or voltage, is the energy difference per unit charge between two points in an electric field. It quantifies the work done in moving a charge from one point to another and is directly related to the electric field in a uniform region.

Relationship between Electric Field and Potential Difference

In a uniform electric field, such as that between two parallel plates, the electric field strength is directly related to the potential difference and inversely related to the separation distance according to the formula E = V/d. This relationship allows one to determine the distance between the plates when the voltage and field strength are known.

Electric Field

The electric field represents the force per unit charge that a charged particle experiences in a region of space. In the context of parallel plates, the electric field is uniform, meaning its magnitude and direction are constant throughout the space between the plates.

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