Question
(I) What is the magnitude of the electric force of attraction between an iron nucleus $(q= + 26e)$ electron if the distance between them is 1.5 $\times$ 10$^{-12}$m?
Step 1
The charge of the iron nucleus is $q= + 26e$ and the charge of an electron is $-e$. The distance between them is $r=1.5 \times 10^{-12}m$. The elementary charge $e$ is $1.6 \times 10^{-19} C$. Show more…
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(I) What is the magnitude of the electric force of attraction between an iron nucleus $(q=+26 e)$ and its innermost electron if the distance between them is $1.5 \times 10^{-12} \mathrm{m}$ ?
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