Question
(I) What is the maximum efficiency of a heat engine whose operating temperatures are 560$^\circ$C and 345$^\circ$C?
Step 1
The formula to convert Celsius to Kelvin is K = C + 273.15. Therefore, the high temperature (T1) in Kelvin is 560 + 273.15 = 833.15 K and the low temperature (T2) in Kelvin is 345 + 273.15 = 618.15 K. Show more…
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