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(I) What is the weight of a 68-kg astronaut ($a$) on Earth, ($b$) on the Moon ($g =1.7 m/s^2$) ($c$) on Mars ($g = 3.7 \,m/s^2$) ($d$) in outer space traveling with constant velocity?

a) $670 \mathrm{N}$b) $120 \mathrm{N}$c) $250 \mathrm{N}$d) $0$

Physics 101 Mechanics

Chapter 4

DYNAMICS: NEWTON'S LAWS OF MOTION

Section 1

Force

Newton's Laws of Motion

Applying Newton's Laws

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uh, so we're going to be solving problem two and checked her for of the gang Coy physics textbook and were given that there's a sixty eight kilogram astronaut. We're as to find his wage. That's the mass of the astronaut. Or has to find his weight on Earth on the moon and on Mars as well as in outer space. Traveling a constant velocity to part a, um, wait on earth we know that way is a force. Maybe Reese thinking about weight is almost just like mass. But masses, um, and inherit property of an object. And the weight is really a force that depends on the acceleration due to gravity. So I'LL label it W um but this is really force of gravity, usually labeled FT physics textbooks and this sequel to the Mass, just like any force mass times acceleration, except for the celebration, is Teo and on Earth. We know that this is nine point eight approximately nine point eight meters per second squared to play in the mass at the same time sixty eight times bring create, and this will be in new ten's kilograms nears per second squared, and we can put that into a calculator. Get six hundred sixty six point four and remember, we only want report. The number of significant digits that we're using, which is to significant, is it's nine point eight sixty eight. So this is roughly six hundred seventy millions. Some part B for asked to find this fur on the moon where were given that he's equal to one point seven communes per second squared. So can we just use the same formula, her weight being Mt. And he just We're gonna play these numbers in the calculator. Still the sixty eight kilograms. And now we're not going to use nine point eight years for second squared. That's exploration due to gravity on Earth. Money's the one point seven. If they told us. Given the problem for the acceleration due to gravity on the moon and then approximating Teo to significant digits, you should get one hundred twenty Nunes part See, we're just going to do the exact same thing. They also tell us acceleration due to gravity. But on Mars three point seven years per second squared, Yeah, still using the same mask. It's all about the same astronaut. Sixty eight kilograms. Oops! And the answer of you should get for that just plugging into calculator approximating Turn fifteen unions and then party his work. It's different because we're now told that the asteroids in outer space not on a planet, not feeling gravity and he's trailing a constant velocity and on velocity is constant. It means that acceleration is zero draw narrow that this implies equal zero because, remember, the acceleration is stuff have lost e changes in time, but it's constant. That's what we're told in the problem. And then wait is a force. This's equal to M A. But one a zero means equal to zero. So travelling and constant velocity in outer space, there's just no forces acting on the asteroid, so thank you for listening.

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