00:01
For this problem, we have three equations, and for each equation, we are going to name the water -soluble product, and we are going to write the net ionic equation.
00:12
Let's start with our first equation by assigning states to each one of our products.
00:19
If i check my solubility rules, i'll see that the copper 2 sulfide is insoluble water, in water, therefore it is my precipitate.
00:28
And hydrochloric acid is an acid, so it's aqueous.
00:34
The water -sliable product in problem one is hydrochloric acid.
00:42
Now, let's write acid.
00:46
Let's write the net ionic equation.
00:52
Look at the hcl, the aqueous product.
00:56
The aqueous product yields two hydrogen ions and two chloride ions.
01:01
That means that our two hydrogen ions and our two chloride ions are going to be our spectator ions.
01:12
Writing the equation with the spectator ions left out will give us our net ionic equation.
01:27
And here is our net ionic equation.
01:30
Number one, done.
01:32
For a second problem, we are going to assign states, and if we check our solubility rules, we'll see that potassium chloride is soluble in water, and calcium carbonate is not.
01:47
It's our precipitate...