00:01
Okay, so we want to give the akin, the created the following products.
00:03
And in the first one, we have an 11 carbon chain.
00:12
So on carbon 2 and 3, we have ketones.
00:20
And on carbon 8, we have a ketone as well.
00:29
So here's the outahead.
00:32
On carbon 11, 11, 10, 9, 8.
00:37
So, um, we know, because we only have one product, we started from a ring structure and broke it open.
00:46
So one possibility is a 10 carbon ring and in order for that to get a key to it on this carbon we'd have to have a methyl group so if we start with a 10 carbon ring so you can draw a cyclohexane and then just erase the middle part and if we put the alken right here and the methyl group right here so this will be carbon one and this will be two three 4, 5, 6, 7, 8, 9, 10, 11.
01:43
Okay, so this is going to be, 11 will be the aldehyde when traded with o 3 and dimethyl sulfide.
01:53
So, carbon, 3 needs ketone, and 7th carbon 8, too.
02:05
So if we break the tip and we'll get the products.
02:11
Okay, for b, we have a 9 carbon chain with formaldehyde as a side product...