Question
Identify the atom whose electron configuration is $[\mathrm{Ne}] 3 s^{2} 3 p^{3} .$ How many unpaired electrons are there in the ground state of this atom?
Step 1
The electron configuration of Neon (Ne) is $1s^{2} 2s^{2} 2p^{6}$. So, the given electron configuration can be written as $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}$. Show more…
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