00:01
So given our equation x minus 2 squared plus y minus 3 squared equals 4, to find the center in radius, we can think back to our general form, x minus h squared plus y minus k squared is equal to radius squared.
00:16
So we can tell that just by looking at this, 2 is h, and then 3 is k, and then since 4 is 2 squared, r is 2.
00:28
So our circle has a center at 2 -3 and radius of 2.
00:40
So to sketch this, we'd have a circle would center about here with radius 2, and this would be our circle.
00:53
So the domain is just a set of x values that our circle contains.
01:04
So looking at the graph of the circle, you can see that this end of the circle, the leftmost edge of the circle is going to be our minimum x and the rightmost edge of the circle is the maximum x.
01:19
Same for the y's where this is the minimum y and this is the maximum y...