00:01
Okay, so here we have the function f of x equals 5x to the 2 5ths minus 2x.
00:15
So the first derivative is going to be 2x to the minus 3 fifths minus 2.
00:24
Second derivative is going to be negative 6 fifths x to the minus 8 over 5.
00:36
Okay.
00:36
Make a couple observations the second derivative's always negative because x to an even power is going to be positive and then we're multiplying by a negative number so always concave down it's good to know all right and what about the critical points when f prime is zero let's see you want two to equal to x to the negative three -fifths well that's going to be one equals x to the negative of three -fifths and that's just going to give us x is equal to one.
01:23
But we also go to consider the case where f prime isn't defined.
01:28
That's going to be at x equals zero.
01:30
So you have two critical points.
01:34
All right.
01:37
And so if we look, so at one, we can use the second derivative test.
01:43
So f double prime of one, we know it's going to be less than zero.
01:47
So that tells us that the point, uh, one, see, one, comma 3 is going to be a local max.
02:02
But then at 0, the second derivative at 0 is undefined.
02:06
So we need to do a little bit more work.
02:09
Well, if you look at a negative number here, we're going to have a negative minus another negative.
02:17
So that's going to be negative to the left of 0.
02:23
And then what about to the right of 0? okay, well, let's see.
02:34
So to the right of zero, we're going to plug in, say, a half, we're going to get two.
02:41
We're going to get something that's also negative.
02:47
Okay, so we're going to be, let's see.
03:08
So let's look.
03:13
So we have zero, and we want to look at f prime...