00:01
So in this problem, we are asked to find the molecular geometry and electron pair geometry of each of the following molecules or polyethomic ions.
00:10
So we'll first have to draw the lewis structure.
00:13
In order to do that, find the number of valance electrons.
00:16
So for example, for i have six, we have six fluorines and one iodine.
00:21
Each of these contributes seven valence electrons.
00:24
So seven times seven is 49.
00:25
It is a charge of positive one.
00:27
We have to subtract one.
00:28
And we get 48 total valence electrons.
00:31
Then count the valence electrons in the loose structure to make sure it matches.
00:35
So we have one, two, three, four, five, six of the phalan electrons being used because we have eight around each of the fluorines, and then we're not counting the ones around the iodine twice.
00:48
So we do six times eight, that's 48, so that's correct, and it's going to look like that.
00:52
Iodine can expand its valence.
00:54
And we can take a look at the chart here to see what kind of geometry that is.
00:59
We see that is octahedral.
01:01
So this is octahedral geometry.
01:04
So we move over here, and this is carbon tetrafluoride.
01:09
So if you take a look at that, you will recognize that at tetrahedral because we have four bonds to the central atom...