00:01
We want to identify which of these hydrogens are going to be pro r and pro s.
00:07
Now, what we are going to do, since on this carbon here, we have the two hydrogens.
00:16
We're going to replace one of the hydrogens with its, or one of its isotopes, deuterium.
00:23
So let's first replace this one facing forward with a deuterium, and then figure out if that now is going to be r or s.
00:33
So remember that deuterium has the same atomic number as hydrogen, since they're just isotopes of each other.
00:42
So in the tiebreaker of what has higher priority for r &s, since it goes atomic number, then atomic weight, deuterium would have the larger atomic weight, so that would be our higher priority group.
00:58
So we're going to have 4 -3, and then we need to decide, well, what has a higher priority? this oxygen or this carbon? well, oxygen has a higher atomic number, so we'd have one going to the left, and then two going towards our carbon there.
01:11
And notice that this rotates counterclockwise, and so that's going to be s.
01:20
Because remember when we draw an s, that first curve we draw goes counterclockwise.
01:25
At least that's the way i remember it.
01:28
So this is going to be pro s.
01:31
And since these are the same groups, if you were to just move that deuterium to the, the other side, it would give us the other orientation.
01:40
So pro r.
01:44
Now we can come up here and do the same thing...