00:01
To determine what element x is, we need to count valence electrons and determine what element would provide the appropriate number of valence electrons for the lewis structure.
00:15
So this lewis structure has a 2 minus charge.
00:19
So we have a total of 1, 2, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, valence electrons.
00:29
2 of them are due to the negative charge.
00:32
So that means that would bring us down to 12.
00:35
So that means each of these must have six valence electrons.
00:39
So this would come from group 6a or group 16, such as s2, 2 minus.
00:46
For this next one, we have four oxygen surrounding x, and we have a 2 minus charge.
00:53
So we have a total of 8, 16, 24, 32 valence electrons.
01:01
Two of them come from the negative charge.
01:07
So we're now down to 30.
01:09
Each oxygen brings in six.
01:14
Six times four is 24.
01:16
30 minus 24 is six.
01:19
So that means this needs to have six valence electrons.
01:22
So it would also come from group six or 16...