00:01
This question is, it asks to identify the orbitals in each of the atoms that form the bonds in h3cn.
00:08
How many sigma and how many pi bonds form? so first of all, let's draw the lewis structure.
00:23
So this ends up being the lewis structure.
00:28
Now, let's identify the orbitals.
00:31
So in this case, we know we have sp3 hybridization on this central carbon.
00:41
So we have sb3 hybridized orbitals.
00:44
And then we have the 1s orbitals of the hydrogen atoms, also participating in bonding with the sp3 hybrid orbitals from the carbon.
01:01
So on this carbon, we have sp hybridization, because we have two electron groups, one single bond and one triple bond...