Question
Identify the oxidizing and reducing agents in the following:(a) $\mathrm{Sn}(s)+2 \mathrm{H}^{+}(a q) \longrightarrow \mathrm{Sn}^{2+}(a q)+\mathrm{H}_{2}(g)$(b) $2 \mathrm{H}^{+}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{Fe}^{2+}(a q) \longrightarrow 2 \mathrm{Fe}^{3+}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)$
Step 1
Therefore, Sn is the reducing agent. On the other hand, the oxidation state of H changes from +1 to 0, which means it gains electrons. Therefore, H$^{+}$ is the oxidizing agent. Show more…
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