00:01
So this is a pretty common type of exam question.
00:03
I had these problems multiple times on my orgo exams.
00:08
You get the product and the reactants.
00:10
You have to identify the reagents.
00:12
So let's get started.
00:14
We have five schemes here.
00:16
So the first is going from benzene to some kind of a propyl carbonyl substitute, right? so a three -carbon acyl group.
00:25
So that is, that looks like friedelcraft's acillation.
00:30
So therefore, we're going to need aluminum chloride or aluminum bromide or iron bromide or iron chloride, whatever lewis acid you want to use.
00:37
And then you have to identify the right acid chloride.
00:40
So that's going to be a three carbon acyl group, one, two, three, plus the acid.
00:45
That will give us that first molecule.
00:50
Second, nothing's happening on the ring.
00:52
We're actually reacting the acyl group with something that removes the carbonyl.
00:59
And that looks like to be the only thing you know that does that right now, which is catalytic hydrogen.
01:07
So then you have to react it with hydrogen on palladium on carbon to remove that you hydrogenate the carbonyl and reduce it to a methylene group to get you probal benzene.
01:21
Next, more chemistry on the ring again.
01:24
You're doing a bromination at the paraposition while the propyl group is activating the ring towards orthobal...