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Problem 37 Medium Difficulty

Identify the unknown particles X and X' in the following nuclear reactions:
a) $\mathrm{X}+_{2}^{4} \mathrm{Hc} \rightarrow_{12}^{24} \mathrm{Mg}+_{0}^{1} \mathrm{n}$
b) $_{92}^{295} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow_{38}^{90} \mathrm{Sr}+\mathrm{X}+2_{0}^{1} \mathrm{n}$
c) $2_{1}^{1} \mathrm{H} \rightarrow \frac{2}{1} \mathrm{H}+\mathrm{X}+\mathrm{X}^{\prime}$

Answer

\frac{212}{83} N e+\frac{4}{2} H e \rightarrow \frac{24}{12} M g+\frac{1}{0} n

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Top Physics 103 Educators
Marshall S.

University of Washington

Farnaz M.

Other Schools

Aspen F.

University of Sheffield

Meghan M.

McMaster University

Video Transcript

It's the number 37. I'm basically supposed to fill in the blanks in each one of these equations. These were actions. Mmm. Excuse me. So I'm gonna go across and look at my atomic numbers on the bottom. We're thinking this is my number of protons. After the reaction, I have 12 before the reaction here's to. So there must be another 10 and then I can go ahead and look on the periodic table and see what has 10 pro tones. That's gonna be neon. And I go across looking my mass numbers. Also, uh, on this side equation has 24 here and another 15 25 here on this other question have four. So I need 21 more to make. 25. 25 Mean 25 on the side. 25 on that side port. Be Oh, I have I'm gonna work with my, uh, protons in the bottom. First have 92 on this side, and I have 38 so far. So I take 92 minds, the 38 I have and you can tell I need 54 more. I look on the periodic table and I see number 54 z non and now for mass numbers. Here I have 2 35 from the Iranian, plus another one from the from the neutron here. So on this later had to 36 on this side, I need to 36. So I already have a 90. And here I have to Don't forget this cowfish in front. So I have 92 already. So to 36 minus the 92 I have you tell I need 1 44 and then for this last one again. I have a coalition of friend here. So for my atomic number to work out, I've got two on this side. I only have one on this side. So I need another proton. But I can't have any more mass because here I already have two on the mass and two on the mass. So what has a positive charge but no mass? That's gonna be a positron. And then when every of a pope positron, you also have a neutrino

University of Virginia
Top Physics 103 Educators
Marshall S.

University of Washington

Farnaz M.

Other Schools

Aspen F.

University of Sheffield

Meghan M.

McMaster University