Question
Identify what is being oxidized and reduced in this redox equation by assigning oxidation numbers to the atoms.$$2 \mathrm{NO}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{NOCl}$$
Step 1
The oxidation number of an atom in its elemental state is always zero. Therefore, the oxidation number of nitrogen (N) in NO is +2 and that of oxygen (O) is -2. The oxidation number of chlorine (Cl) in Cl2 is 0. Show more…
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