Question
If 0.090909 is approximately equal to $\frac{1}{11}$,, then the approximate value of 0.454545 is(a) $\frac{4}{11}$(b) $\frac{5}{11}$(c) $\frac{45}{11}$(d) $\frac{6}{11}$
Step 1
090909 can be expressed as a fraction. We know that 0.090909 is approximately equal to \(\frac{1}{11}\). Show more…
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