Question
If $0<x<\frac{\pi}{2}$, then(A) $\cos (\sin x)>\cos x$(B) $\cos (\sin x)<\cos x$(C) $\cos (\sin x)>\sin (\cos x)$(D) $\cos (\sin x)<\sin (\cos x)$
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This is a well-known property of the sine function. Show more…
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$\mathrm{f} 0<x<\frac{\pi}{2}$, then (A) $\frac{2}{\pi}>\frac{\sin x}{x}$ (B) $\frac{2}{\pi}<\frac{\sin x}{x}$ (C) $\frac{\sin x}{x}<1$ (D) $\frac{\sin x}{x}>1$
Assertion: If $0<x<\frac{\pi}{2}$, then $\cos (\sin x)>\cos x>\sin$ $(\cos x)$ Reason: $\sin x<x$ for $0<x<\frac{\pi}{2}$.
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