Question
If $1, \omega, \omega^{2}$ are the cube roots of unity, then the value of $\left(1+5 \omega^{2}+\omega^{4}\right)\left(1+5 \omega+\omega^{2}\right)$ is(a) 16(b) 64(c) 28(d) 18
Step 1
This means that $\omega^3 = 1$. We also know that $1 + \omega + \omega^2 = 0$. Show more…
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