Question
If $10 \mathrm{~kg}$ of rock salt is placed in water, it dissolves at a rate proportional to the amount of salt still undissolved. If $2 \mathrm{~kg}$ dissolve during the first 10 minutes, how long will it be until only 2 kg remain undissolved?
Step 1
This can be represented by the differential equation: \[ \frac{dS}{dt} = k(S_0 - S) \] where \(S_0\) is the initial amount of salt, \(S\) is the amount of salt at time \(t\), and \(k\) is the proportionality constant. Show more…
Show all steps
Your feedback will help us improve your experience
Raj Bala and 64 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If 10 kg of rock salt is placed in water, it dissolves at a rate proportional to theamount of salt still undissolved. If 2kg dissolve during the first 10 minutes, how long will it be until only 2kg remain undissolved?
The rate at which salt dissolves in water is directly proportional to the amount that remains un-dissolved. If ten pounds of salt is placed in a container of water and four pounds dissolves in twenty minutes, how much longer long will it take for two more pounds to dissolve? Answer: About 15.9 minutes.
525 g of salt is placed in a jar of water. After 1 minute, 115 g of salt remains undissolved. How long will it take until only 20 g of salt is undissolved? Assume the salt decays exponentially. Give your answer to the nearest unit.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD