Question
If $10 \mathrm{~mL}$ of an elixir containing $50 \mathrm{mg} / 10 \mathrm{~mL}$ active ingredient is diluted to $12 \mathrm{~mL}$, what will be the final strength of active ingredient?
Step 1
Given that the original elixir contains 50 mg of active ingredient per 10 mL, we can calculate the total amount of active ingredient in the original elixir as follows: $50 \mathrm{mg/10mL} \times 10 \mathrm{mL} = 50 \mathrm{mg}$ Show more…
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