If 100 mL of an elixir containing 3 mg / 5 mL theophylline is diluted to 150 mL, what will be

Step 1: Calculate the total amount of theophylline in the original elixir. Given that the elixir

Question

If $100 \mathrm{~mL}$ of an elixir containing $3 \mathrm{mg} / 5 \mathrm{~mL}$ theophylline is diluted to $150 \mathrm{~mL}$, what will be the final strength of theophylline?

    If $100 \mathrm{~mL}$ of an elixir containing $3 \mathrm{mg} / 5 \mathrm{~mL}$ theophylline is diluted to $150 \mathrm{~mL}$, what will be the final strength of theophylline?

Essential Math and Calculations for Pharmacy Technicians

Indra K. Reddy,… 1st Edition

Chapter 7, Problem 10

Instant Answer

Step 1

Given that the elixir contains 3 mg of theophylline in every 5 mL, we can calculate the total amount of theophylline in 100 mL of elixir: $3 \mathrm{mg} / 5 \mathrm{mL} = x \mathrm{mg} / 100 \mathrm{mL}$ $ x = 3 \mathrm{mg} \times \frac{100 \mathrm{mL}}{5 Show more…

Show all steps

Thanks for your feedback!

If $100 \mathrm{~mL}$ of an elixir containing $3 \mathrm{mg} / 5 \mathrm{~mL}$ theophylline is diluted to $150 \mathrm{~mL}$, what will be the final strength of theophylline?

Play audio

Feedback

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Conservation of Mass

The principle of conservation of mass states that during the dilution process, the total mass of the solute remains constant even though the volume of the solution increases. This concept is crucial when calculating the new concentration after dilution, as it ensures that the amount of the substance does not change despite the addition of more solvent.

Concentration

Concentration is a measure of the amount of a substance (solute) present in a given volume of solution. It is usually expressed as a ratio, such as milligrams per milliliter (mg/mL), and it quantifies how much of the solute is dissolved in the solvent.

Dilution

Dilution involves adding more solvent to a solution, which increases the total volume while the amount of solute remains unchanged. This process results in a lower concentration of the solute because the same quantity is spread over a larger volume.

Please give Ace some feedback