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If 14.5 $\mathrm{kJ}$ of heat were added to 485 $\mathrm{g}$ of liquid water, how much would its temperature increase?

$7.15^{\circ} \mathrm{C}$

Chemistry 101

Chapter 5

Thermochemistry

Rice University

Drexel University

Brown University

University of Toronto

Lectures

05:27

In chemistry, a chemical r…

06:42

In chemistry, energy is wh…

01:10

How much would the tempera…

00:29

When $47.5 \mathrm{J}$ of …

00:56

The temperature of 756 $\m…

01:01

$\cdots$ Thermal energy is…

00:41

How much heat is evolved w…

01:48

If a reaction produces 1.5…

03:45

You heat $250 \mathrm{g}$ …

01:14

If it takes 526 J of energ…

01:23

A 45 -kg sample of water a…

02:50

If $125.6 \mathrm{kJ}$ of …

01:36

Calculate the amount of en…

01:08

(I) How much heat (in joul…

08:18

How much heat (in kJ) is e…

03:50

When 1.045 g of CaO is add…

00:31

03:46

The temperature of a sampl…

03:55

00:27

If $57 \mathrm{J}$ of heat…

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So this question is asking us how much with the temperature increase if I added 14.5 killer jewels of 485 grams of water. So we're really just gonna use the Q equals M asked. This was the heat out to tea and just played in some numbers. So remember that Q has to be in jewels, so we first have to convert 14.5 killer jewels into 1 14,500 jewels. And I did that by just multiplying by 1000 which is our conversion factor. So if I plug in some numbers, we get 14,500 equals 485 grams. Art is a key of water is 4.18 tools for Graham's times degrees Celsius a man Delta T, which is what we're looking for If I divine through by 485 and 4.18 divided by for 85 times 4.18 it's gonna give me 7.15 equals Delta T. So that's gonna be our change in temperature 7.15 degrees Celsius.

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