Question
If $150 \mathrm{~mL}$ of $0.055 \mathrm{M} \mathrm{HNO}_{3}$ are needed to completely neutralize $1.48 \mathrm{~g}$ of an impure sample of sodium hydrogen carbonate (baking soda), what percent of the sample is baking soda?
Step 1
First, we need to find the moles of HNO3 in the solution. We can do this using the formula: moles = Molarity × Volume (in Liters). moles of HNO3 = 0.055 M × 0.150 L = 0.00825 moles Show more…
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