If 2 is added to the numerator of a fraction, it reduces to ((1)/(2)) and if 1 is subtracted fro

Name: Problem 38, Chapter 2: CUET UG : Section I and Section III Exam 2024 (English Edition) - 20 Practice Tests (1000 Solved Questions) with Free Access to Online Tests
Uploaded: 2020-09-01T19:45:42-08:00
Duration: 2 min 29 s
Channel: Harsh Gadhiya
Description: If 2 is added to the numerator of a fraction, it reduces to ((1)/(2)) and if 1 is subtracted from the denominator; it reduces to ((1)/(3)). Find the fraction. (a) (5)/(7) (b) (1)/(10) (c) (2)/(5) (d) (3)/(10)

step 1 In this question, I have to find out which of these three fractions is closest to 1 by 2, which

Question

If 2 is added to the numerator of a fraction, it reduces to $\left(\frac{1}{2}\right)$ and if 1 is subtracted from the denominator; it reduces to $\left(\frac{1}{3}\right)$. Find the fraction. (a) $\frac{5}{7}$ (b) $\frac{1}{10}$ (c) $\frac{2}{5}$ (d) $\frac{3}{10}$

   If 2 is added to the numerator of a fraction, it reduces to $\left(\frac{1}{2}\right)$ and if 1 is subtracted from the denominator; it reduces to $\left(\frac{1}{3}\right)$. Find the fraction.
(a) $\frac{5}{7}$
(b) $\frac{1}{10}$
(c) $\frac{2}{5}$
(d) $\frac{3}{10}$

CUET UG : Section I and Section III Exam 2024 (English Edition) - 20 Practice Tests (1000 Solved Questions) with Free Access to Online Tests

EduGorilla Prep… 1st Edition

Chapter 2, Problem 38

Instant Answer

Solved by Expert Harsh Gadhiya

09/01/2020

Step 1

Step 2: According to the first condition, if 2 is added to the numerator, the fraction becomes $\frac{x + 2}{y}$ and this is equal to $\frac{1}{2}$. We can set up the equation: \[ \frac{x + 2}{y} = \frac{1}{2} \] Step 3: Cross-multiply to eliminate the Show more…

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If 2 is added to the numerator of a fraction, it reduces to $\left(\frac{1}{2}\right)$ and if 1 is subtracted from the denominator; it reduces to $\left(\frac{1}{3}\right)$. Find the fraction. (a) $\frac{5}{7}$ (b) $\frac{1}{10}$ (c) $\frac{2}{5}$ (d) $\frac{3}{10}$

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Key Concepts

Systems of Linear Equations

Once the problem is translated into algebraic equations, it often results in a system of linear equations. This concept involves solving these equations simultaneously using methods like substitution or elimination to find the unique values of the unknowns.

Algebraic Translation

This concept involves converting the verbal statements of a problem into algebraic equations. By carefully interpreting the conditions given (such as adding or subtracting a constant from the numerator or denominator), one can form equations that accurately represent the relationships between the unknown quantities.

Operations on Fractions

Understanding how operations affect fractions is crucial. This includes knowing the effect of altering the numerator or denominator on the value of the fraction and using techniques such as cross-multiplication to solve equations that involve fractions.

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