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If $\$ 2000$ is invested at an interest rate of $3.5 \%$ per year, compounded continuously, find the value of the investment after the given number of years.a. 2 yearsb. 4 yearsc. 12 years

(a) $\$ 2145.02$(b) $\$ 2300.55$(c) $\$ 3043.92$

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 2

The Natural Exponential Function

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we are given indiscretion that our principal amount equals $2000. The rate of interest is 3.5% on its compounded continuously and the formalize B E a Stow Arthuis for A B and given time equals two years Onda. We plug all the values and to get amount as 2001. $45.2 for beat Me argument. But he equals four years. So we plug the equals two on, dressed Up for our values to get the amount as 2300.55 dollars. And for party, we are given that p equals 12 years. So we plug in all the given information in our form. Love, I'm get the amount as $3043.92.

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