Question
If $(2,3,5)$ is one end of a diameter of the sphere $x^{2}+y^{2}$ $+z^{2}-6 x-12 y-2 z+20=0$, then the coordinates of the other end of the diameter are $[2007]$(A) $(4,9,-3)$(B) $(4,-3,3)$(C) $(4,3,5)$(D) $(4,3,-3)$
Step 1
Step 1: The given equation of the sphere can be rewritten as follows: \[(x-3)^2 + (y-6)^2 + (z-1)^2 = 26\] Show more…
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