Question
If $3^{19}[x+i y]=\left[\frac{3}{2}+\frac{\sqrt{3}}{2} i\right]$ and $x=k y$, then $k$ equals(a) $\frac{1}{\sqrt{3}}$(b) $\sqrt{3}$(c) $\frac{-1}{\sqrt{3}}$(d) $-\sqrt{3}$
Step 1
We can rewrite the right side of the equation by taking $\sqrt{3}$ as a common factor, which gives us $\sqrt{3}\left[\frac{1}{2}+\frac{1}{2} i\right]$. Show more…
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