If 36.2 mL of 0.158 M CaCl2 solution is added to 37.5 mL of 0.149 M Na2 CO3, what mass of calciu

step 1 It is this question 37 from chapter 15, and we are trying to find how much mass of calcium carbo

If 36.2 mL of 0.158 M CaCl2 solution is added to 37.5 mL of...

If 36.2 $\mathrm{mL}$ of 0.158 $\mathrm{M} \mathrm{CaCl}_{2}$ solution is added to 37.5 $\mathrm{mL}$ of $0.149 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3},$ what mass of calcium carbonate, $\mathrm{CaCO}_{3},$ will be precipitated? The reaction is $$ \begin{array}{l}{\mathrm{CaCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \rightarrow} \\ {\quad \mathrm{CaCO}_{3}(s)+2 \mathrm{NaCl}(a q)}\end{array} $$

If 36.2 $\mathrm{mL}$ of 0.158 $\mathrm{M} \mathrm{CaCl}_{2}$ solution is added to 37.5 $\mathrm{mL}$ of $0.149 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3},$ what mass of calcium carbonate, $\mathrm{CaCO}_{3},$ will be precipitated? The reaction is
$$
\begin{array}{l}{\mathrm{CaCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \rightarrow} \\ {\quad \mathrm{CaCO}_{3}(s)+2 \mathrm{NaCl}(a q)}\end{array}
$$

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Key Concepts

Stoichiometry

Stoichiometry involves using a balanced chemical equation to determine the quantitative relationships between reactants and products. It provides the mole ratios needed to calculate how much product can be formed from the given amounts of reactants.

Limiting Reagent

The limiting reagent in a chemical reaction is the reactant that is completely consumed first, thus determining the maximum amount of product that can be produced. Identifying the limiting reagent is essential for accurate yield predictions.

Molarity and Volume Conversion

Molarity is a measure of concentration expressed in moles of solute per liter of solution. By multiplying molarity by the volume of solution, one can calculate the number of moles of a given reactant, which is fundamental for stoichiometric calculations.

Mole-to-Mass Conversion

Converting from moles to mass involves using the molar mass of the substance. This conversion is critical when the problem requires an answer in grams, linking the abstract mole concept to a measurable quantity.

Precipitation Reaction

A precipitation reaction occurs when two aqueous solutions combine to form an insoluble solid, known as a precipitate. Understanding this type of reaction is crucial for predicting the formation and mass of the precipitate from the reactants.

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