Question
If $(4+3 i)(1-2 i)=a+b i,$ then what is the value ofa? (Note that $i=\sqrt{-1} )$
Step 1
We start by expanding this equation using the FOIL method (First, Outer, Inner, Last). This gives us: \[4*1 + 4*(-2i) + 3i*1 + 3i*(-2i) = a+bi\] Simplifying this gives us: \[4 - 8i + 3i - 6i^2 = a+bi\] Show more…
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