Question
If $A$ and $B$ are (not necessarily abelian) groups, prove that $A \cap B=$ $A \times B$ (direct product) in Groups. For readers familiar with group theory, prove that $A \sqcup B=A * B$ (free product) in Groups.
Step 1
The intersection \( A \cap B \) of two groups \( A \) and \( B \) consists of all elements that are in both \( A \) and \( B \). The direct product \( A \times B \) consists of ordered pairs \( (a, b) \) where \( a \in A \) and \( b \in B \). Show more…
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