Question
If $a, b, c$ are in G.P. and $x$ is the A.M. between $a$ and $b, y$ the A.M. between $b$ and $c$, then(A) $\frac{a}{x}+\frac{c}{y}=1$(B) $\frac{a}{x}+\frac{c}{y}=2$(C) $\frac{1}{x}+\frac{1}{y}=\frac{2}{b}$(D) None of these
Step 1
Step 1: Since $a, b, c$ are in geometric progression, we have $b^2 = ac$. Show more…
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