Question
If a ball is thrown into the air with a velocity of 40 $\mathrm{ft} / \mathrm{s}$ , itsheight (in feet) after $t$ seconds is given by $y=40 t-16 t^{2}$ .Find the velocity when $t=2$
Step 1
We are given the height equation of a ball thrown into the air as \( y = 40t - 16t^2 \), where \( y \) is the height in feet and \( t \) is the time in seconds. We need to find the velocity of the ball at \( t = 2 \) seconds. Show more…
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If a ball is thrown into the air with a velocity of 40 $\mathrm{ft} / \mathrm{s}$ , its height (in feet) after $t$ seconds is given by $y=40 t-16 t^{2}$ . Find the velocity when $t=2$ .
Derivatives
Derivatives and Rates of Change
If a ball is thrown into the air with a velocity of $ 40 ft/s $, its height (in feet) after $ t $ seconds is given by $ y = 40t - 16t^2 $. Find the velocity when $ t = 2 $.
Limits and Derivatives
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