00:01
Problem 16.
00:03
In this problem, a ball is thrown straight upward with initial velocity v.
00:08
So let us say this is the ball and it is thrown upward with velocity v and it reaches up to a height h.
00:19
So this distance is h.
00:23
And here, its instantaneous velocity becomes zero.
00:29
All right.
00:30
Now, now in second, second part they are saying that they are doubling the initial speed of the ball and what will be the maximum height reached so now we are throwing this ball with speed to v and what will be its new maximum height let us say it is capital h so we have to determine the value of capital h here again at maximum height we know that its instantaneous velocity will be zero.
01:05
So we can apply energy conservation here.
01:08
So if we apply energy conservation for this for first part of the problem, so it's initially there was if we if we choose reference line for potential energy at the point of projection to be zero.
01:23
Therefore initial kinetic, therefore total kinetic energy of the ball has been converted to potential energy at the maximum height.
01:32
Therefore half m v square was equals to m g h that is total initial kinetic energy was converted into potential energy where m is mass of the ball.
01:47
So we can cancel this term...