00:01
We are given for a diffraction grading.
00:04
The third order maxima occurs at an angle of 78 .4 degrees.
00:11
And the wavelength of the light used is 681 nanometers.
00:16
Now we know that the formula that governs diffraction gratings is d sine theta is equal to m lambda, where d is the distance between two slits.
00:29
But we can recast this formula in terms of the number of slits per cent, uh, per unit length using n equal to 1 by d.
00:38
If n is the number of slits per unit length, and then d is the distance between two slits.
00:44
And this is how they're related.
00:46
By using this, we can recast this formula as sine theta is equal n m lambda.
00:55
Now that we have this, for part a, we simply find out the value of n.
01:04
We know that n is equal to sine theta.
01:07
By m lambda.
01:09
So using the data we are given, sine 78 .4 degrees divided by m is 3 times 681 nanometers is 681 times 10 bar minus 9.
01:25
This comes out to be 4 .9795 into 10 bar 5.
01:32
But notice that this is an si units, and hence the units will be per meter.
01:37
To make it per centimeter, we divide this by 100.
01:42
Which gives us 4 ,800 slits per centimeter.
01:51
Notice that i have rounded this to three significant digits and you get this...