00:01
Suppose a is the area under the curve f of x equals sine x over the interval 0 to pi over 2, and r subn be the approximation to a with n subintervals using right endpoints.
00:16
From exercise 27, the equation that relates a and r subn has been deduced to arrive at the inequality, r subn minus a.
00:25
This is less than the product between the width of each n strips, this one, and the net change of f from a to b, that is f of b minus f of a, which is this one.
00:44
Suppose r sub n minus a is less than 0 .0 .001.
00:50
Since a and b represents 0 and pi over 2 respectively, then we have pi over 2 minus 0 all over n, times f of pi over 2 minus f of 0 this is equal to 0 .0 .0 .01.
01:15
Since f of x is sine x, then we have pi over 2 over n times f of pi over 2, that's sine pi over 2, minus f of 0, which is sine of 0...