Question
If a man has an average useful power output of $40.0 \mathrm{W}$ what minimum time would it take him to lift fifty $10.0-\mathrm{kg}$ boxes to a height of $2.00 \mathrm{m} ?$
Step 1
It can be calculated using the formula: \[P = \frac{W}{\Delta t}\] where \(P\) is power, \(W\) is work done and \(\Delta t\) is the time taken. Show more…
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(a) What is the average useful power output of a person who does $6.00 \times 10^{6} \mathrm{J}$ of useful work in $8.00 \mathrm{h}$ ? (b) Working at this rate, how long will it take this person to lift $2000 \mathrm{kg}$ of bricks $1.50 \mathrm{m}$ to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
(a) What is the average useful power output of a person who does $6.00 \times 10^{6} J$ of useful work in 8.00 h? (b) Working at this rate, how long will it take this person to lift 2000 kg of bricks 1.50 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)
A crane uses $2 \mathrm{~kW}$ to raise a $100-\mathrm{kg}$ box $20 \mathrm{~m}$. How much time does it take?
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