Question
If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be(a) $2: 1$(b) $1: 2$(c) $1: 3$(d) $3: 1$
Step 1
The reaction is given by: \[ N_2 + 3H_2 \rightarrow 2NH_3 \] Show more…
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If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be: (a) $2: 1$ (b) $1: 2$ (c) $1: 3$ (d) $3: 1$
If a mixture containing 3 mole of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of initial and final volumes under the same temperature and pressure would be: (a) $3: 1$ $\square$ (b) $1: 3$ $\mathrm{F}$ (c) $1: 2$ $\square$ (d) $2: 1$ $\Gamma$
Forty per cent of a mixture of $0.2 \mathrm{~mol}$ of $\mathrm{N}_{2}$ and $0.6 \mathrm{~mol}$ of $\mathrm{H}_{2}$ react to give $\mathrm{NH}_{3}$ according to the equation: $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$ at constant temperature and pressure. Then, the ratio of the final volume to the initial volumes of gases is (a) $4: 5$ (b) $5: 4$ (c) $7: 10$ (d) $8: 5$
Chemical Equilibrium
Exercises I
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