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Hey, everyone.
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This is question number three from chapter 21.
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In this problem, we're told that we are releasing a proton and an electron from we're releasing a proton and electron, and they're released two times 10 to the minus 10 meters apart.
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We're asked to find the acceleration of each particle.
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So we are asked for acceleration, so immediately you should be thinking f equals m .a.
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Newton's second law, and we're looking for acceleration.
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We aren't given in this question the mass of a proton electron, but that is something a constant that you would be given on a test or you should be expected to know.
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So then all we have left is force.
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And when we're dealing with particles, i've already written it over here, we have kulams law, which can help us find force.
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So k is our constant.
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Q1, q2, those are the charges of proton and electron, and then r squared radius between them, so we can actually go ahead and solve for this force.
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So f equals k is kulams constant, which is 9 times 10 to the 9th, and that is newton's times meter squared per coolum squared.
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All right, and then we have q1 and q2.
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As we know, protons and electrons, their charges are equal and opposite.
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So they will exert a force on each other, but equal and opposite.
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It so we can just use the magnitude and square it.
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So 1 .6 times 10 to the negative 10th, 10 to minus 19, excuse me, cool arms, and then square that because we have a proton and electron, and then our radius is 2 times 10 to the minus 10th meters, and we square that, and that will give us a force equal to, if you plug that into your calculator, 5 .76 times 10 to the minus 9th meters...