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If a reaction produces 1.506 $\mathrm{kJ}$ of heat, which is trapped in 30.0 $\mathrm{g}$ of water initially a6.5 $^{\circ} \mathrm{C}$ in a calorimeter like that in Figure $5.12,$ what is the resulting temperature of the water?

$T_{\mathrm{f}}=38.5^{\circ} \mathrm{C}$

Chemistry 101

Chapter 5

Thermochemistry

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So in this problem, we're trying to find the final temperature, considering that 1.506 killer Jules is dissolved in 30.0 grams of water with a starting temperature the initial of 26.5 degrees Celsius. Remember, to solve these types of problems, we're gonna use the equation. Q equals M s, Delta T. And so am is gonna be our mass as our specific eat and Melvin T is gonna be our change in temperature. Also remember that Q is measured in jewels so that we first have to convert 1.506 killer Jules into regular tool. So to do that, we just multiply. By 1000 you get 1506 jewels. So them again is plugging some numbers into this equation. Our mass is gonna be 30 grams because of the heat is 4.18 tools for Graham's times degree Celsius and our delta T is temperature final minus 26.5 degrees Celsius. If we divide through by 30 and 4.18 that gives us 12.0 equals t f minus 26.5, meaning T. Our final temperature is gonna be 38.5 degrees Celsius. Hope that house

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