The mass is given by the integral of the density over the length of the rod. For the left half, the density is $\rho_1=1 \mathrm{g} / \mathrm{cm}$ and the length is 50 cm (half of 1 m). So, the mass of the left half is
\[m_1 = \int_0^{50} \rho_1 dx = \int_0^{50} 1
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