00:01
So let's get right at it.
00:01
And we are given this equation and asked to show this if the water is deep.
00:07
Ok, so what we're looking for is when d is very large.
00:16
So when d is very large, let's take a look at this.
00:20
So the limit of d to infinity, v squared, equals the limit of gl over 2 pi d to infinity times the tangent of h to pi d over l.
00:44
This will equal g over l 2 pi in the limit of d to infinity tangent h over l.
01:06
And that will equal gl over 2 pi times 1 equals gl over 2 pi.
01:16
So we can approximate the tangent h when d is very large.
01:25
When d is very large, this approaches.
01:36
Let me look at this.
01:39
This approaches one.
01:42
So this section right here approaches one.
01:47
Thus, d will be equal to the square root of gl over 2 pi.
01:55
High part two says where is my part two um table oopsie gotta go over here everything's taking a long time here arrange surface area temperature directions these guidelines use guidelines what what is this one? i am on 826.
02:46
If water.
02:47
Ok, for b, b says if water is shallow, then we are asked to use the maclaurin series for the tangent h to show that v is approximately equal to the square root of g d.
03:30
So thus, in shallow water, the velocity of the wave tends to be independent of the length of the wave.
04:02
Okay, let's do this one...