Question
If $a>b>0$ and $f(\theta)=\frac{\left(a^{2}-b^{2}\right) \cos \theta}{a-b \sin \theta}$, find the max.value of $f(\theta)$
Step 1
Step 1: First, we can rewrite the function $f(\theta)$ as follows: \[f(\theta)=\frac{\left(a^{2}-b^{2}\right) \cos \theta}{a-b \sin \theta} = \frac{(a+b)(a-b) \cos \theta}{a(1 - \frac{b}{a} \sin \theta)}\] Show more…
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