00:02
So if the problem here states that we have a root of a non -zero number, well, let's take the nth root of 1.
00:12
So we would have 1 in complex or in polar form would be, would be cosine of 0 plus i sign of 0.
00:23
I sign of 0.
00:24
And so to find the nth root of this, to find the nth root of this, well, this becomes, this becomes cosine of 0.
00:33
Remember we would have 1 to the 1 over n but this just this just is 1 so we don't include this but then we would have cosine of 0 over n plus 2 pi k over n plus i sign of 0 over n plus 2 pi k over n and so let's simplify this well we would have we would have cosine of of 2 pi n over n and then we'd have minus 2 pi plus i sign of 2 pi n over n minus 2 pi well if we look at this we if we cross out this n divide this n out we would have 2 pi minus 2 pi so this whole this whole angle goes to 0 so we have cosine of 0 for the nth root nth root we would have cosine of 0 plus i sine of 0.
01:37
So let's treat this as our mth root.
01:39
So in other words, let's say s is equal to 1.
01:43
So our last term for the nth and the nth term, we would have s, we would have s to the w minus to the w to the n minus 1.
01:55
To the n minus 1...