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If A.M. and G.M. of roots of a quadratic equation are 8 and 5, respectively, then obtain the quadratic equation.
Precalculus
Chapter 9
Sequences and Series
Section 3
Series
Introduction to Sequences and Series
Campbell University
University of Michigan - Ann Arbor
Idaho State University
Utica College
Lectures
07:16
In mathematics, a continuo…
04:09
01:18
Solve the quadratic equati…
00:27
Solve each equation. Be su…
01:00
Without solving each equat…
00:46
Use the discriminant to de…
01:03
In this section, there is …
03:37
Solve quadratic equation b…
01:09
03:41
Complex Solutions of a Qua…
02:20
Solve the equation by usin…
04:42
Solve each equation by fac…
we have a problem number 32. All right is given that the A M and G M of the roots of equality equation are eight and five respectively. Then obtained the quality equation. So if Uh huh alpha and better. Uh The roots of quality question than I am is al fabulous bitter by two. That a thematic mean equal to eight which means alphabet equal to 16. Sorry alpha plus beat equals extend place. We take all to 16. No secondly the GM alpha into beta. Under the square root is a cultural five because GM of alpha and beta will be in the hood of alpha beta. So alphabet A will be equal to 25. Now if Alfa and beta the roots so quiet equation becomes access choir minus some of routes that is alpha plus between two X plus access choir my room plus a product that is alphabet to equal to zero. So we have access square minus alpha blockers. Beta is 16 16 X plus 25 equal to zero. They should be the correct answer. Thank you so much.
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