Composition

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Stephen P.

Drexel University

Allea C.

University of Maryland - University College

JH

Brown University

Video Transcript

So in this problem, we're working with sodium and a and it's been told. But the atomic mass of sodium is 22.9. And this means that the this is basically telling us the weight of one Adam in atomic mass units. All right, so the first question is, if we were gonna have 1.98 turns 10 to the 13 um, brands of sodium. How many sodium atoms would be present in the sample? They 1.98 times 10 to 13. Ah, am use Hope it into grants. Oh, so Odeon of just elemental. So you So what would we do? Um, according toward just intuitive people, what we would have thought to do was to take this sample the mass of the sample invited by the mass of one Adam. I've told him trying to point my mind. Wealth am use. All right, so this division would weigh upto a quint 61 two times tend to the 11 Teoh 11 on 11 sodium Adam. So there some 8.612 time 10 to 11 sodium Adams in this sample. Next. If we were to then have this 3.1 Time Center. 23 stadium. Adams. How many in use with that? We have to be. We have this extremely large number three times 10 to 23 and just remind ourselves this is how many atoms of sodium. But we have. If you want to know how much all of these same Adams wouldn't way out together. So what we would do simply is to multiply that number by number by the mass of each individual. Sodium Adam Just reading 2.99 a. M. So number everyone of these millions of 1,000,000 of millions Adam sodium atoms way these much, So we just have to multiply more that ends up giving us sits. Point in mine one mine times 10 to the 24 AM use of sodium

McMaster University

Composition