00:01
This question is first asking us to write the balanced equation for the reaction.
00:06
So, let's take a look at our reactants.
00:09
Well, we have some diatomic blue spheres, so we have some n2s, and we also have some diatomic white spheres, so those are diatomic hydrogens.
00:21
Okay, so those are our reactants.
00:22
What about our products? so we have two different possibilities for our products.
00:27
And some of them, we have three hydrogens and one, one nitrogen, okay.
00:41
And we also have one where we have a diatomic blue sphere, so an n2.
00:53
And then products b, we have only these three h's one n.
01:03
So what do we call the 3h1n? well, we can write that simply as nh3.
01:14
Okay.
01:15
And as you can see here, the n2 is actually a leftover from our reactants.
01:22
So that would be an excess, essentially, right? so we wouldn't include that in our products.
01:31
So let's write the actual balance equation.
01:33
Well, we have n2 plus h2 producing nh3.
01:40
So how do we balance this? well, we have two n2s on the left, right? so we want to put a coefficient of 2 in front of the nh3.
01:48
So now our nitrogens are balanced.
01:54
What about our hydrogens? we have two hydrogens on the left.
01:57
We have a total of six hydrogens, right? because if there's three hydrogens here times two, like it's a six hydrogens.
02:04
So we want to put a coefficient of three in front of the h2...